How do you integrate x3+x2(3x2+2x) using substitution?

1 Answer
Mar 3, 2018

x3+x2(3x2+2x)dx=23(x3+x2)32+C

Explanation:

Let's set u=x3+x2.

Differentiating, we get

dudx=3x2+2x

We can change this derivative to a differential by moving dx to the right side (multiplying both sides by it)

du=(3x2+2x)dx

Look at our integral, x3+x2(3x2+2x)dx

We see (3x2+2x)dx appears in the integral; thus, we can replace it with du. Furthermore, we already said u=x3+x2, so we can replace everything under the root with u.

x3+x2(3x2+2x)dx=udu

Let's rewrite this with exponents:

udu=u12du

Recall that xadx=xa+1a+1+C; where C is just the constant of integration; therefore,

u12du=u12+112+1+C=u3232+C=23u32+C

Let's rewrite in terms of x, recalling that u=x3+x2:

23u32+C=23(x3+x2)32+C