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How do you integrate $\int x {(1 + x^{2})}^{\frac{1}{3}}$ $int x(1 + x^2)^(1/3)$ ?

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Apr 1, 2015

Use substitution with $u = 1 + x^{2}$ $u = 1+x^2$ so $d u = 2 x d x$ $du = 2x dx$ and the integral becomes:

$\frac{1}{2} \int u^{\frac{1}{3}} d u$ $1/2 int u^(1/3) du$

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