How do you integrate $int x^nsinx^(n-1)dx$ using integration by parts?

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Answer 1 · 2015-11-07T17:35:37

If you are not looking for an answer, you could, I suppose, use $u=x^2$ and $dv=x^(n-2)sin(x^(n-1))dx$ to get

$-1/(n-1)x^2cos(x^(n-1))-2/(n-1) int xcos(x^(n-1))dx$

How do you integrate int x^nsinx^(n-1)dxint x^nsinx^(n-1)dx using integration by parts?