How do you integrate $int x(x+1)^8$ using substitution?

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Answer 1 · 2017-01-16T10:30:12

$(x+1)^10/10-(x+1)^9/9+C$

Substitute $u=x+1$ and you get:
$int(u-1)u^8du$
$=int u^9du - int u^8du$
$=u^10/10-u^9/9+C$
Substituting back $u=x+1$ gives the answer.

How do you integrate int x(x+1)^8int x(x+1)^8 using substitution?