Question

How do you integrate `int xe^x dx` using integration by parts?

Answer 1

`I = e^x(x - 1) + c`

Explanation:

`I = intxe^xdx`

Say `u = x` so `du = 1`, `dv = v = e^x`

`I = xe^x - inte^xdx`
`I = xe^x - e^x`
`I = e^x(x - 1) + c`