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How do you integrate ${(x + 1)}^{2} d x$ $(x+1)^2dx$ ?

1 Answer

Oct 18, 2016

$\frac{{(x + 1)}^{3}}{3}$ $((x+1)^3 )/3$ + c

Explanation:

Let u = x + 1
du = dx
$\int u^{2} d x$ $intu^2dx$ = $\frac{u^{3}}{3}$ $( u^3) / 3$ + c
= $\frac{{(x + 1)}^{3}}{3}$ $( (x+1)^3)/3$ + c

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