Question

How do you integrate `x/((ln3)(x^2 + 4))`?

Answer 1

`intx/((ln3)(x^2+4))dx`

`ln3` is a constant so this turns down to,

`=> 1/ln3intx/(x^2+4)dx =1/ln3 int1/2*(2x)/(x^2+4)dx=1/(2ln3)int(2x)/(x^2+4)dx`

The numerator is the derivative of the denominator so,

`=>1/(2ln3)lnabs(x^2+4) + C`