Question

How do you long divide `(12y^3 + 18y^2 + 24y) ÷ (6y)`?

Answer 1

`2y^2+3y+4`

Explanation:

you must divide each term of the polynomial by 6y:

`(12y^cancel3)/(6cancely)+(18y^cancel2)/(6cancely)+(24cancely)/(6cancely)`

`2y^2+3y+4`