How do you long divide #(3x^2+x-10) / (6x+1)#?

1 Answer
Barney V.
Aug 25, 2017

#color(magenta)(1/2x+1/12#

Explanation:

#color(white)(.)color(white)(..........)ul(1/2x+1/12)#
#6x+1|3x^2+0+x-10#
#color(white)(.............)ul(3x^2+0+1/2x)#
#color(white)(...........................)1/2x-10#
#color(white)(...........................)ul(1/2x+1/12)#
#color(white)(..................................)-10 1/12#

#color(magenta)((3x^2+x-10) / (6x+1) = 1/2x+1/12# and remainder of#color(magenta)((-10 1/12)/(6x+1)#

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