Question

How do you long divide `(6x^2+7x+5) / (2x+5)`?

Answer 1

`" "3x-4 +25/(2x+5)`

Supporting Brian's answer but with a small amount of further explanantion.

Explanation:

`" "3x-4`
`" "2x+5color(white)(.)bar(| color(white)(.)6x^2+7x+5)`
`" "underline(6x^2+15x )" " larr" Subtract "3x(2x+5)`
`" "0x^2-8x+5" " larr" Bring down the +5"`
`" "underline(-8x-20)" " larr" Subtract "-4(2x+5)`
`" "0x+25`

Remainder `-> +25" giving " +25/(2x+5)`

So the final answer is:

`" "3x-4 +25/(2x+5)`