How do you long divide $6 x^{3} + 27 x - 19 x^{2} - 15 \div 3 x - 5$ $6x^3 + 27x - 19x^2 - 15 div 3x -5$ ?

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How do you long divide $6 x^{3} + 27 x - 19 x^{2} - 15 \div 3 x - 5$ $6x^3 + 27x - 19x^2 - 15 div 3x -5$ ?

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Answer 1 · 2016-11-08T09:09:26

The answer is $2 x^{2} - 3 x + 4 + \frac{5}{3 x - 5}$ $2x^2-3x+4+5/(3x-5)$

Explanation:

Let's do the long division
$a a a$ $color(white)(aaa)$ $6 x^{3} - 19 x^{2} + 27 x - 15$ $6x^3-19x^2+27x-15$ $a a a$ $color(white)(aaa)$ $∣$ $∣$ $3 x - 5$ $3x-5$
$a a a$ $color(white)(aaa)$ $6 x^{3} - 10 x^{2}$ $6x^3-10x^2$ $a a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaaa)$ $∣$ $∣$ $2 x^{2} - 3 x + 4$ $2x^2-3x+4$
$a a a a a$ $color(white)(aaaaa)$ $0 - 9 x^{2} + 27 x$ $0-9x^2+27x$
$a a a a a a a$ $color(white)(aaaaaaa)$ $- 9 x^{2} + 15 x$ $-9x^2+15x$
$a a a a a a a a a a a$ $color(white)(aaaaaaaaaaa)$ $0 + 12 x - 15$ $0+12x-15$
$a a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaaa)$ $+ 12 x - 20$ $+12x-20$
$a a a a a a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaaaaaaa)$ $0 + 5$ $0+5$

The quotient is $= (2 x^{2} - 3 x + 4)$ $=(2x^2-3x+4)$ and the remainder is $= 5$ $=5$

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How do you long divide $6 x^{3} + 27 x - 19 x^{2} - 15 \div 3 x - 5$ $6x^3 + 27x - 19x^2 - 15 div 3x -5$ ?

1 Answer

Explanation:

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Science

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How do you long divide 6x3+27x−19x2−15÷3x−5 6x^3 + 27x - 19x^2 - 15 div 3x -5?

1 Answer

Explanation:

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How do you long divide $6 x^{3} + 27 x - 19 x^{2} - 15 \div 3 x - 5$ $6x^3 + 27x - 19x^2 - 15 div 3x -5$ ?