How do you long divide #n^2 - 11n - 26# by #n+2#? Precalculus Real Zeros of Polynomials Long Division of Polynomials 1 Answer Rafael Oct 20, 2015 #n-13# Explanation: I'll just show you my solution here. #" "ul(n-13)# #n+2" "|n^2-11n-26# #color(white)(n+2)" "ul(-n^2-2n)# #color(white)(n+2)" "-13n-26# #color(white)(n+2)" "ul(13n+26)# #color(white)(n+2)" "0# So, #n^2-11n-26# divided by #n+2# is #color(blue)(n-13)#. Answer link Related questions What is long division of polynomials? How do I find a quotient using long division of polynomials? What are some examples of long division with polynomials? How do I divide polynomials by using long division? How do I use long division to simplify #(2x^3+4x^2-5)/(x+3)#? How do I use long division to simplify #(x^3-4x^2+2x+5)/(x-2)#? How do I use long division to simplify #(2x^3-4x+7x^2+7)/(x^2+2x-1)#? How do I use long division to simplify #(4x^3-2x^2-3)/(2x^2-1)#? How do I use long division to simplify #(3x^3+4x+11)/(x^2-3x+2)#? How do I use long division to simplify #(12x^3-11x^2+9x+18)/(4x+3)#? See all questions in Long Division of Polynomials Impact of this question 1838 views around the world You can reuse this answer Creative Commons License