How do you long divide $(x^{2} + 4 x + 1)$ $(x^2+4x+1)$ by $x - 5$ $x-5$ ?

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Answer 1 · 2015-10-04T14:08:07

See explanation...

You can long divide polynomials in a similar way to the way you long divide numbers.

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or you can just long divide the coefficients like this:

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Either way, we find $\frac{x^{2} + 4 x + 1}{x - 5} = (x + 9)$ $(x^2+4x+1)/(x-5) = (x+9)$ with remainder $46$ $46$

Here's another example, that I animated to illustrate the process...

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How do you long divide (x2+4x+1) (x^2+4x+1) by x−5x-5?