Question

How do you long divide `(x^2 + 6x +5)/(x^2-3x-4)`?

Answer 1

`(x+5)/(x-4)`

Explanation:

By factoring we have:
`(x^2+6x+5)/(x^2-3x-4)=(cancel((x+1))(x+5))/(cancel((x+1))(x-4))`