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How do you long divide $\frac{x^{2} - x - 12}{x - 4}$ $(x^2-x-12)/(x-4)$ ?

1 Answer

Aug 5, 2015

I found: $\frac{x^{2} - x - 12}{x - 4} = x + 3$ $(x^2-x-12)/(x-4)=x+3$

Explanation:

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