How do you long divide #(x^3+3x^2+3x+1)/(x+1)#?

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Answer 1 · 2016-11-03T14:23:58

ans. #(x+1)^2#.

we know #(a+b)^3=a^3+3a^2b+3ab^2+b^3#
hence #(x+1)^3=x^3+3x^2+3x+1#
so #(x^3+3x^2+3x+1)/(x+1)#
=#(x+1)^3/(x+1)#
=#(x+1)^2#.

Answer 2 · 2016-11-03T17:56:14

#x^2+2x+1#

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