How do you long divide $\frac{- x^{5} + 3 x^{4} + 4 x^{2} + 2 x - 7}{x^{2} - 5 x + 2}$ $(-x^5 + 3x^4 + 4x^2 + 2x - 7)/(x^2 - 5x + 2)$ ?

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How do you long divide $\frac{- x^{5} + 3 x^{4} + 4 x^{2} + 2 x - 7}{x^{2} - 5 x + 2}$ $(-x^5 + 3x^4 + 4x^2 + 2x - 7)/(x^2 - 5x + 2)$ ?

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Answer 1 · 2015-12-29T13:10:05

Long divide the coefficients to find:

$\frac{x^{5} + 3 x^{4} + 4 x^{2} + 2 x - 7}{x^{2} - 5 x + 2}$ $(x^5+3x^4+4x^2+2x-7)/(x^2-5x+2)$

$= - x^{3} - 2 x^{2} - 8 x - 32 + \frac{- 142 x + 57}{x^{2} - 5 x + 2}$ $= -x^3-2x^2-8x-32+(-142x+57)/(x^2-5x+2)$

Explanation:

I like to just long divide the coefficients, not forgetting to include a $0$ $0$ for any missing powers of $x$ $x$ (in this case $x^{3}$ $x^3$ in the dividend).

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The process is similar to long division of numbers.

The result is a quotient $- x^{3} - 2 x^{2} - 8 x - 32$ $-x^3-2x^2-8x-32$ and remainder $- 142 x + 57$ $-142x+57$

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How do you long divide $\frac{- x^{5} + 3 x^{4} + 4 x^{2} + 2 x - 7}{x^{2} - 5 x + 2}$ $(-x^5 + 3x^4 + 4x^2 + 2x - 7)/(x^2 - 5x + 2)$ ?

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Explanation:

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How do you long divide −x5+3x4+4x2+2x−7x2−5x+2(-x^5 + 3x^4 + 4x^2 + 2x - 7)/(x^2 - 5x + 2)?

1 Answer

Explanation:

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How do you long divide $\frac{- x^{5} + 3 x^{4} + 4 x^{2} + 2 x - 7}{x^{2} - 5 x + 2}$ $(-x^5 + 3x^4 + 4x^2 + 2x - 7)/(x^2 - 5x + 2)$ ?