How do you multiply #2(6+10)#?

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Answer 1 · 2016-05-08T16:36:55

32

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#2xx16=32#

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suppose you had #2(a+b)#

This is 2 lots of #(a+b)#

So #2(a+b)" "->" "(a+b)+(a+b)#

Which is: #a+a+b+b = 2a+2b#

From this you can observe that you get the same answer if you just multiply everything inside the brackets by 2.

Suppose you had #=-3(a+b) = -3a-3b#

Suppose you had #-3(a-4b) = -3a+12b#

Suppose you had #5(1/(5a)+b/10) =5/(5a)+(5b)/10= 1/a+b/2#