How do you multiply $\frac{2}{7} \cdot - 3.5$ $2/7 \cdot -3.5$ ?

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Answer 1 · 2014-10-01T05:34:10

It is very easy to multiply two numbers;

$(\frac{2}{7})$ $(2/7)$ x (-3.5)

-3.5 can be written as $(- \frac{3.5}{1})$ $(-3.5/1)$

I can also write as

$(\frac{2}{7})$ $(2/7)$ x $(- \frac{3.5}{1})$ $(-3.5/1)$

Multiplying the numerators and denominators , we get;

( 2 x -3.5 / 7 x 1 )

$(- \frac{7}{7})$ $(-7/7)$ = -1

How do you multiply 27⋅−3.52/7 \cdot -3.5?