How do you multiply #3y^2z(2y^2z + 4yz - y + z)#? Algebra Polynomials and Factoring Multiplication of Polynomials by Binomials 1 Answer Don't Memorise Jun 26, 2015 # =color(green)(6y^4z^2+ 12y^3z^2 -3y^3z + color(green)(3y^2z^2) # Explanation: # color(green)(3y^2z)(2y^2z+4yz-y+z)# # =color(green)(3y^2z) . (2y^2z) + color(green)(3y^2z) . (4yz)- color(green)(3y^2z) .( y)+ color(green)(3y^2z) . (z)# # =color(green)(6y^4z^2+ 12y^3z^2 -3y^3z + color(green)(3y^2z^2) # Answer link Related questions What is FOIL? How do you use the distributive property when you multiply polynomials? How do you multiply #(x-2)(x+3)#? How do you simplify #(-4xy)(2x^4 yz^3 -y^4 z^9)#? How do you multiply #(3m+1)(m-4)(m+5)#? How do you find the volume of a prism if the width is x, height is #2x-1# and the length if #3x+4#? How do you multiply #(a^2+2)(3a^2-4)#? How do you simplify #(x – 8)(x + 5)#? How do you simplify #(p-1)^2#? How do you simplify #(3x+2y)^2#? See all questions in Multiplication of Polynomials by Binomials Impact of this question 3385 views around the world You can reuse this answer Creative Commons License