How do you multiply #4y(2y-3)-5(2-y)#?

1 Answer
Don't Memorise
Jun 26, 2015

# = color(blue)(8y^2 - 7y -10)#

Explanation:

# color(blue)(4y)(2y-3)-color(green)(5)(2-y)#

#= [color(blue)(4y) . (2y) + color(blue)(4y) . (-3)] - [color(green)(5).(2) +color(green)(5).(-y)]#

# = color(blue)(8y^2 - 12y) - color(green)(10 + 5y)#
combining
# = color(blue)(8y^2 - 7y -10)#

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