Question

How do you multiply `(4y + 8)/ (y^2 - 2y)*(y - 2)/(y+2)`?

Answer 1

The answer is `4/y`

Explanation:

Given that
`\frac{4y+8}{y^2-2y}\cdot\frac{y-2}{y+2}`
`=\frac{4(y+2)}{y(y-2)}\cdot\frac{y-2}{y+2}`
`=4/y\cdot \frac{y+2}{y-2}\cdot\frac{y-2}{y+2}`
`=4/y\cdot \frac{y+2}{y+2}\cdot\frac{y-2}{y-2}`
`=4/y\cdot 1\cdot 1`
`=4/y`