How do you multiply $(5.8 \times 10^{- 6}) (3 \times 10^{- 8})$ $(5.8\times 10^ { - 6} ) ( 3\times 10^ { - 8} )$ ?

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Answer 1 · 2017-06-22T05:56:35

$(5.8 \times 10^{- 6}) (3 \times 10^{- 8}) = 1.74 \times 10^{- 13}$ $(5.8xx10^(-6))(3xx10^(-8))=1.74xx10^(-13)$

We are multipying two numbers given in scientific notation and it is expected to give result too in scientific notation.

So $(5.8 \times 10^{- 6}) (3 \times 10^{- 8})$ $(5.8xx10^(-6))(3xx10^(-8))$

= $(5.8 \times 3) \times (10^{- 6} \times 10^{- 8})$ $(5.8xx3)xx(10^(-6)xx10^(-8))$

= $17.4 \times 10^{- 6 + (- 8)}$ $17.4xx10^(-6+(-8))$

= $(1.74 \times 10) \times 10^{- 14}$ $(1.74xx10)xx10^(-14)$

= $1.74 \times 10^{1 - 14}$ $1.74xx10^(1-14)$

= $1.74 \times 10^{- 13}$ $1.74xx10^(-13)$

How do you multiply (5.8\times 10^ { - 6} ) ( 3\times 10^ { - 8} )(5.8×10−6)(3×10−8)(5.8\times 10^ { - 6} ) ( 3\times 10^ { - 8} )?