How do you multiply #(8y^6 + 4y^4 -12y^2) (3/4y^2 +2)#? Algebra Polynomials and Factoring Multiplication of Polynomials by Binomials 1 Answer Nallasivam V Aug 25, 2015 #6y^8 +19y^6 - y^4 - 24y^2# Explanation: #24/4y^8+12/4y^6-36/4y^4+16y^6+8y^4-24y^2# #6y^8 + 3y^6 -9y^4 + 16y^6 + 8y^4 - 24y^2# #6y^8 +19y^6 - y^4 - 24y^2# Answer link Related questions What is FOIL? How do you use the distributive property when you multiply polynomials? How do you multiply #(x-2)(x+3)#? How do you simplify #(-4xy)(2x^4 yz^3 -y^4 z^9)#? How do you multiply #(3m+1)(m-4)(m+5)#? How do you find the volume of a prism if the width is x, height is #2x-1# and the length if #3x+4#? How do you multiply #(a^2+2)(3a^2-4)#? How do you simplify #(x – 8)(x + 5)#? How do you simplify #(p-1)^2#? How do you simplify #(3x+2y)^2#? See all questions in Multiplication of Polynomials by Binomials Impact of this question 1396 views around the world You can reuse this answer Creative Commons License