Question

How do you multiply `(m - 1) (m^2 + 2m + 6)`?

Answer 1

First you multiply the `m` with all the others in the second group, and then the `-1`

`=m*(m^2+2m+6)+(-1)*(m^2+2m+6)`

`=(m.m^2+m*2m+m*6)+(-1m^2-2m-6)`

`=m^3+2m^2+6m-1m^2-2m-6`. now add like powers:

`=m^3+(2-1)m^2+(6-2)m-6`

`=m^3+m^2+4m-6`