How do you multiply # (r-4)/(5r)=(1/(5r)) + (1)#? Algebra Rational Equations and Functions Clearing Denominators in Rational Equations 1 Answer Don't Memorise May 21, 2015 # (r-4)/(5r)=(1/(5r)) + (1)# # (r-4)/(5r) -1/(5r) = 1 xx (5r)/(5r)# # (r-4)/(5r) -1/(5r) = (5r)/(5r)# # (r-4 -1)/cancel(5r) = (5r)/cancel(5r)# #r-5 =5r# #-5 =4r# #r = -5/4# Answer link Related questions What is Clearing Denominators in Rational Equations? How do you solve rational expressions by multiplying by the least common multiple? How do you solve #5x-\frac{1}{x}=4#? How do you solve #-3 + \frac{1}{x+1}=\frac{2}{x}# by finding the least common multiple? What is the least common multiple for #\frac{x}{x-2}+\frac{x}{x+3}=\frac{1}{x^2+x-6}# and how do... How do you solve #\frac{x}{x^2-36}+\frac{1}{x-6}=\frac{1}{x+6}#? How do you solve by clearing the denominator of #3/x+2/x^2=4#? How do you solve #2/(x^2+2x+1)-3/(x+1)=4#? How do you solve equations with rational expressions #1/x+2/x=10#? How do you solve for y in #(y+5)/ 2 - y/3 =1#? See all questions in Clearing Denominators in Rational Equations Impact of this question 3264 views around the world You can reuse this answer Creative Commons License