How do you normalize $(- 2 i + - 1 j + 2 k)$ $(-2i + -1j + 2k)$ ?

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How do you normalize $(- 2 i + - 1 j + 2 k)$ $(-2i + -1j + 2k)$ ?

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Answer 1 · 2018-06-18T06:06:01

The answer is $= < - \frac{2}{3}, - \frac{1}{3}, \frac{2}{3} >$ $=<-2/3,-1/3,2/3>$

Explanation:

To normalize a vector $\to u$ $vecu$ , divide the vector by the modulus of the vector

$ˆ u = \frac{\to u}{∣ ∣ ∣ ∣ \to u ∣ ∣ ∣ ∣}$ $hatu=vecu/||vecu||$

Here,

$\to u = < - 2, - 1, 2 >$ $vecu= <-2,-1,2>$

The modulus is

$∣ ∣ ∣ ∣ \to u ∣ ∣ ∣ ∣ = | | < - 2, - 1, 2 > | | = \sqrt{{(- 2)}^{2} + {(- 1)}^{2} + {(2)}^{2}}$ $||vecu|| = ||<-2,-1,2>|| = sqrt((-2)^2+(-1)^2+(2)^2)$

$= \sqrt{4 + 1 + 4}$ $=sqrt(4+1+4)$

$= \sqrt{9}$ $=sqrt9$

$= 3$ $=3$

Therefore,

$ˆ u = \frac{1}{3} \cdot < - 2, - 1, 2 > = < - \frac{2}{3}, - \frac{1}{3}, \frac{2}{3} >$ $hatu=1/3*<-2,-1,2> = <-2/3,-1/3,2/3>$

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How do you normalize $(- 2 i + - 1 j + 2 k)$ $(-2i + -1j + 2k)$ ?

1 Answer

Explanation:

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How do you normalize (−2i+−1j+2k) (-2i + -1j + 2k)?

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How do you normalize $(- 2 i + - 1 j + 2 k)$ $(-2i + -1j + 2k)$ ?