How do you normalize # (-2i + -1j + 2k)#?

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Answer 1 · 2018-06-18T06:06:01

The answer is #=<-2/3,-1/3,2/3>#

To normalize a vector #vecu#, divide the vector by the modulus of the vector

#hatu=vecu/||vecu||#

Here,

#vecu= <-2,-1,2>#

The modulus is

#||vecu|| = ||<-2,-1,2>|| = sqrt((-2)^2+(-1)^2+(2)^2)#

#=sqrt(4+1+4)#

#=sqrt9#

#=3#

Therefore,

#hatu=1/3*<-2,-1,2> = <-2/3,-1/3,2/3>#