How do you normalize #(- 2i - j - k)#?
1 Answer
Aug 14, 2017
Explanation:
Normalization of a vector is the process of finding a unit vector in the same direction of the vector in question.
The equation for the normalization of a vector (which I'll call
#(vecv)/(||vecv||)#
where
The magnitude of
#||vecv|| = sqrt((-2)^2 + (-1)^2 + (-1)^2) = color(red)(ul(sqrt6#
Thus, the unit vector (
#hatv = (-2)/(color(red)(sqrt6))hati - 1/(color(red)(sqrt6))hatj - 1/(color(red)(sqrt6))hatk#
#color(blue)(ulbar(|stackrel(" ")(" "hatv = -sqrt(2/3)hati - 1/(sqrt6)hatj - 1/(sqrt6)hatk" ")|)#