How do you normalize #(- 3 i + 12j -5k)#?
1 Answer
Mar 5, 2017
Explanation:
In normalizing the vector we are finding a unit vector (magnitude/length of one) in the same direction as the given vector. This can be accomplished by dividing the given vector by its magnitude.
#u=v/(|v|)#
Given
#|v|=sqrt((v_x)^2+(v_y)^2+(v_z)^2)#
#|v|=sqrt((-3)^2+(12)^2+(-5)^2)#
#|v|=sqrt(9+144+25)#
#|v|=sqrt(178)#
We now have:
#u=(<-3,12,-5>)/sqrt(178)#
Hope that helps!