Question

How do you normalize `(4 i + 4 j + 2 k)`?

Answer 1

Dividing each component by his module

Explanation:

Module of vector is `sqrt(4^2+4^2+2^2)=sqrt36=6`

So the normalized is `4/6veci+4/6vecj+2/6veck=2/3veci+2/3vecj+1/3veck`

Check the answer `sqrt((2/3)^2+(2/3)^2+(1/3)^2)=sqrt1=1`