How do you normalize $(8 i + 12 j + 14 k)$ $(8i + 12j + 14k)$ ?

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How do you normalize $(8 i + 12 j + 14 k)$ $(8i + 12j + 14k)$ ?

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Answer 1 · 2016-02-13T11:10:30

$\to u = \frac{8}{\sqrt{404}} \cdot i + \frac{12}{\sqrt{404}} \cdot j + \frac{14}{\sqrt{404}} \cdot k$ $vec u=8/sqrt 404*i+12/sqrt 404*j+14/sqrt 404*k$

Explanation:

$\to v = (8 i + 12 j + 14 k)$ $vec v=(8i+12j+14k)$
$\to u = \frac{\to v}{∣ ∣ \to v ∣ ∣}$ $vec u=vec v/| vec v|$
$\to u = \frac{8 i + 12 j + 14 k}{\sqrt{8^{2} + 12^{2} + 14^{2}}}$ $vec u=(8i+12j+14k)/sqrt(8^2+12^2+14^2)$
$\to u = \frac{8 i + 12 j + 14 k}{\sqrt{64 + 144 + 196}}$ $vec u=(8i+12j+14k)/sqrt (64+144+196)$
$\to u = \frac{8 i + 12 j + 14 k}{\sqrt{404}}$ $vec u=(8i+12j+14k)/sqrt 404$
$\to u = \frac{8}{\sqrt{404}} \cdot i + \frac{12}{\sqrt{404}} \cdot j + \frac{14}{\sqrt{404}} \cdot k$ $vec u=8/sqrt 404*i+12/sqrt 404*j+14/sqrt 404*k$

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How do you normalize $(8 i + 12 j + 14 k)$ $(8i + 12j + 14k)$ ?

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Math

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How do you normalize (8i+12j+14k) (8i + 12j + 14k) ?

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Explanation:

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How do you normalize $(8 i + 12 j + 14 k)$ $(8i + 12j + 14k)$ ?