How do you perform the operation and write the result in standard form given $- (\frac{1}{2} + \frac{5}{2} i) + (\frac{5}{3} + \frac{11}{3} i)$ $-(1/2+5/2i)+(5/3+11/3i)$ ?

Question

How do you perform the operation and write the result in standard form given $- (\frac{1}{2} + \frac{5}{2} i) + (\frac{5}{3} + \frac{11}{3} i)$ $-(1/2+5/2i)+(5/3+11/3i)$ ?

1 Answer

Impact of this question

1856 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-08-25T11:33:12

$\frac{7}{6}$ $7/6$ + $\frac{7}{6} i$ $7/6i$

Explanation:

$- \frac{1}{2} + \frac{5}{3} = \frac{7}{6}$ $-1/2+5/3=7/6$
$- \frac{5}{2} + \frac{11}{3} = \frac{7}{6}$ $-5/2+11/3=7/6$
Just deal with real part and then the imaginary part separately

Science

Math

Humanities

... and beyond

How do you perform the operation and write the result in standard form given $- (\frac{1}{2} + \frac{5}{2} i) + (\frac{5}{3} + \frac{11}{3} i)$ $-(1/2+5/2i)+(5/3+11/3i)$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you perform the operation and write the result in standard form given −(12+52i)+(53+113i)-(1/2+5/2i)+(5/3+11/3i)?

1 Answer

Explanation:

Related questions

Impact of this question

How do you perform the operation and write the result in standard form given $- (\frac{1}{2} + \frac{5}{2} i) + (\frac{5}{3} + \frac{11}{3} i)$ $-(1/2+5/2i)+(5/3+11/3i)$ ?