How do you plot #5-12i# and find its absolute value?

1 Answer
Apr 21, 2017

Set up a imaginary coordinate plane and plot the point, the absolute value, or the modulus is the length of the line from (0,0)

Explanation:

An imaginary plane is just like your regular #x,y# plane but instead of #y# in the vertical axis we have #i#, starting from #1i,2i, 3i, 4i...#, the x axis remains the same. The point #5-12i# would be a point that is a value of #5# on the horizontal axis and a value of #-12# on the vertical axis, so it'll be a point in the #4th# quadrant. You can find the length of this line from 0,0 graphically or algebraically as shown below.

#|z| = sqrt(a^2 + b^2)# where a is the real part and b the imaginary. So the absolute value of the given term is #sqrt(5^2 + (-12)^2) = sqrt(169)#