How do you prove 1-[2sin^2 (4x)]? Trigonometry Trigonometric Identities and Equations Double Angle Identities 1 Answer Nghi N. Jun 27, 2015 Prove : 1 - 2sin^2 (4x) Explanation: Use the trig identity: cos 2a = 1 - 2sin^2 a 1 - 2sin^2 (4x) = cos 8x Answer link Related questions What are Double Angle Identities? How do you use a double angle identity to find the exact value of each expression? How do you use a double-angle identity to find the exact value of sin 120°? How do you use double angle identities to solve equations? How do you find all solutions for sin 2x = cos x for the interval [0,2pi]? How do you find all solutions for 4sinthetacostheta=sqrt(3) for the interval [0,2pi]? How do you simplify cosx(2sinx + cosx)-sin^2x? If tan x = 0.3, then how do you find tan 2x? If sin x= 5/3, what is the sin 2x equal to? How do you prove cos2A = 2cos^2 A - 1? See all questions in Double Angle Identities Impact of this question 4720 views around the world You can reuse this answer Creative Commons License