How do you prove 1+tan^2 (x) = sec^2 (x)1+tan2(x)=sec2(x)?
1 Answer
Oct 1, 2016
See explanation...
Explanation:
Starting from:
cos^2(x) + sin^2(x) = 1cos2(x)+sin2(x)=1
Divide both sides by
cos^2(x)/cos^2(x) + sin^2(x)/cos^2(x) = 1/cos^2(x)cos2(x)cos2(x)+sin2(x)cos2(x)=1cos2(x)
which simplifies to:
1+tan^2(x) = sec^2(x)1+tan2(x)=sec2(x)