How do you prove 1+tan^2 (x) = sec^2 (x)1+tan2(x)=sec2(x)?

1 Answer
Oct 1, 2016

See explanation...

Explanation:

Starting from:

cos^2(x) + sin^2(x) = 1cos2(x)+sin2(x)=1

Divide both sides by cos^2(x)cos2(x) to get:

cos^2(x)/cos^2(x) + sin^2(x)/cos^2(x) = 1/cos^2(x)cos2(x)cos2(x)+sin2(x)cos2(x)=1cos2(x)

which simplifies to:

1+tan^2(x) = sec^2(x)1+tan2(x)=sec2(x)