How do you prove #1+tan^2 (x) = sec^2 (x)#?
1 Answer
Oct 1, 2016
See explanation...
Explanation:
Starting from:
#cos^2(x) + sin^2(x) = 1#
Divide both sides by
#cos^2(x)/cos^2(x) + sin^2(x)/cos^2(x) = 1/cos^2(x)#
which simplifies to:
#1+tan^2(x) = sec^2(x)#
