How do you prove #Cosx + sinx tanx = secx#?

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How do you prove #Cosx + sinx tanx = secx#?

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Answer 1 · 2018-06-24T00:33:29

Proof in explanation.

Explanation:

Proving #cosx + sinxtanx -= secx#

#RHS = cosx + sinxtanx#
#=cosx + sinx*sinx/cosx#
#=cosx+sin^2x/cosx#
#=cos^2x/cosx +sin^2x/cosx#
#=(sin^2x+cos^2x)/cosx# [Pythagorean identity: #sin^2x+cos^2x=1#]
#=1/cosx#
#=secx = LHS#

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How do you prove #Cosx + sinx tanx = secx#?

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