Question

How do you prove `Cot^2 (theta) + 5 = 6 Cot (theta)`?

Answer 1

Impossible.

Explanation:

It is impossible. Take an example to prove it:
`t = pi/3` --> `cot (pi/3) = sqrt3/3` --> `cot^2 (pi/3) = 3/9 = 1/3`
`1/3 + 5` different to `6(sqrt3/3)`
However, the equation is true when `t = pi/4 + 2kpi`
`t = pi/4` --> cot t = 1 --> `cot^2 t = 1`-->
1 + 5 = 6(1). OK