How do you prove #cot^2 x +csc^2 x = 2csc^2 x - sin^2(2x)-cos^2(2x)#?
1 Answer
Mar 25, 2018
See below.
Explanation:
We have:
#cos^2x/sin^2x + 1/sin^2x = 2/sin^2x - (sin^2(2x) + cos^2x)#
#(cos^2x + 1)/sin^2x = 2/sin^2x - 1#
#(1 - sin^2x + 1)/sin^2x = (2 -sin^2x)/sin^2x#
#(2-sin^2x )/sin^2x = (2 - sin^2x)/sin^2x#
Hopefully this helps!