How do you prove #csc^2 θ+ sec^2 θ = sec^2 θ csc^2 θ#?

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Answer 1 · 2016-05-05T17:45:55

see below

Left Side: #=csc^2theta+sec^2 theta#

#=1/sin^2 theta + 1/cos^2 theta#

#=(cos^2 theta + sin^2 theta)/(sin^2 theta cos^2 theta)#

#=1/(cos^2 theta sin^2 theta)#

#=1/cos^2 theta * 1/sin^2 theta#

#=sec^2 theta csc^2 theta#

#=#Right Side