How do you prove that the limit of #(1-5x) = 16# as x approaches -3 using the epsilon delta proof?
1 Answer
Oct 1, 2016
See proof below.
Explanation:
Given a positive
Now for every
# = abs((-5)(x+3))#
# = abs(-5)abs(x+3)#
# = 5abs(x+3)#
# < 5delta = 5(epsilon/5) = epsilon#
We have shown that for any positive
if
Therefore, by the definition of limit,