How do you prove that (x+pi/4)-(x+pi/4)^3/(3!)+(x+pi/4)^5/(5!)-... = 1-(x-pi/4)^2/(2!)+(x-pi/4)^4/(4!)=...= 1+x-x^2/(2!)-x^3/(3!)+x^4/(4!)+x^5/(5!)-..., x in (-oo, oo)?

1 Answer
Aug 23, 2016

See below

Explanation:

sin(x+pi/4) = cos(x-pi/4) and

sin(x+pi/4) = sqrt(2)/2(sin x + cos x)

so the ask would be

(x+pi/4)-(x+pi/4)^3/(3!)+(x+pi/4)^5/(5!)-cdots = 1-(x-pi/4)^2/(2!)+(x-pi/4)^4/(4!)= sqrt(2)/2(1+x-x^2/(2!)-x^3/(3!)+x^4/(4!)+x^5/(5!)-cdots), x in (-oo, oo)?