How do you put $2 x - 3 y = 6$ $2x-3y=6$ in slope intercept form?

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Answer 1 · 2018-07-26T22:53:38

$y = \frac{2}{3} x - 2$ $y=2/3x-2$

$y = m x + b$ $y=mx+b$ , with slope $m$ $m$ and $y$ $y$ -intercept of $b$ $b$ .

We essentially just want a $y$ $y$ on the left side, so let's subtract 2x# from both sides to get

$- 3 y = - 2 x + 6$ $-3y=-2x+6$

Lastly, let's divide both sides by $- 3$ $-3$ to get

$y = \frac{2}{3} x - 2$ $y=2/3x-2$

Our equation is now in slope-intercept form, where the slope is $\frac{2}{3}$ $2/3$ and our $y$ $y$ -intercept is $- 2$ $-2$ .

Hope this helps!

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