How do you rationalize the Lewis structures of the known compounds #XeF_2#, #XeF_4#, and #XeF_6#?

1 Answer
anor277
Jul 4, 2017

Well for #XeF_2# we gots #8+2xx7=22*"electrons...."#

Explanation:

And for the molecular and electronic geometries we invoke simple VESPER.

For #XeF_2# the electronic geometry is #"trigonal bipyramidal"#; the molecular geometry is #"LINEAR"#....

![alfa-img.com](useruploads.socratic.org)

For #XeF_4#, we have #8+4xx7=36#, #"18 electron pairs"#. the electronic geometry is #"octahedral"#; the molecular geometry is #"SQUARE PLANAR"#....

![alfa-img.com](useruploads.socratic.org)

For #XeF_6#, we got #8+6xx7=50, "25 electron pairs......"#; the central xenon is associated with 6 bonding, and 1 non-bonding pairs of electrons; a conformationally mobile, mono-capped octahedron structure is indicated with respect to the electronic distribution. See here for structure.

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