How do you rationalize the Lewis structures of the known compounds XeF_2, XeF_4, and XeF_6?

1 Answer
Jul 4, 2017

Well for XeF_2 we gots 8+2xx7=22*"electrons...."

Explanation:

And for the molecular and electronic geometries we invoke simple VESPER.

For XeF_2 the electronic geometry is "trigonal bipyramidal"; the molecular geometry is "LINEAR"....

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For XeF_4, we have 8+4xx7=36, "18 electron pairs". the electronic geometry is "octahedral"; the molecular geometry is "SQUARE PLANAR"....

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For XeF_6, we got 8+6xx7=50, "25 electron pairs......"; the central xenon is associated with 6 bonding, and 1 non-bonding pairs of electrons; a conformationally mobile, mono-capped octahedron structure is indicated with respect to the electronic distribution. See here for structure.