How do you remove discontinuity of #f(x) = (x^4 - 1)/(x-1)#? Calculus Limits Classifying Topics of Discontinuity (removable vs. non-removable) 1 Answer GiĆ³ Apr 12, 2015 You can write your numerator as #(x^2-1)(x^2+1)# where #(x^2-1)=(x-1)(x+1)# giving: #f(x)=((x-1)(x+1)(x^2+1))/(x-1)=(x+1)(x^2+1)# Answer link Related questions How do you find discontinuity algebraically? How do you find discontinuity of a piecewise function? How do you find discontinuity points? How do you find the discontinuity of a function? How can you remove a discontinuity? How do i find discontinuity for a function? How do you find a removable discontinuity for a function? How do you find the discontinuity of a rational function? What does discontinuity mean? What does discontinuity mean in math? See all questions in Classifying Topics of Discontinuity (removable vs. non-removable) Impact of this question 2272 views around the world You can reuse this answer Creative Commons License