How do you rewrite #0.75h+1.25b =30# in standard form?

1 Answer
Jan 31, 2015

Either you want #h=# as function of #b#, or the other way around.

Possibility a: #h=f(b)#
(step 1) #b#'s to the right
#0.75h+1.25b=30->0.75h=-1.25b+30#

(step 2) divide everything by 0.75

#h=-1.25/0.75 b+30/0.75=-1 2/3 b+40#

Possibility b: #b=f(h)#
(step 1) #h#'s to the right
#0.75h+1.25b=30->1.25b=-0.75h+30#

(step 2) divide everything by 1.25

#b=-0.75/1.25 h+30/1.25= -3/5h+24#