How do you rewrite (2x^-2 y^2 )/ y^-3 using a positive exponent?

1 Answer
Alan P.
Oct 22, 2015

(2x^(-2)y^2)/(y^(-3)) = (2y^5)/(x^2)

Explanation:

In general
color(white)("XXX")s^(-k) = 1/s^k
and
color(white)("XXX")1(/t^-q) = t^q

(2x^(-2)y^2)/(y^(-3))

color(white)("XXX")=(2y^2)/1 * (x^-2)/1 * 1/(y^(-3))

color(white)("XXX")=(2y^2)/1*1/x^2*y^3/1

color(white)("XXX")=(2y^5)/(x^2)

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