Question

How do you rewrite `(2x^-2 y^2 )/ y^-3` using a positive exponent?

Answer 1

`(2x^(-2)y^2)/(y^(-3)) = (2y^5)/(x^2)`

Explanation:

In general
`color(white)("XXX")s^(-k) = 1/s^k`
and
`color(white)("XXX")1(/t^-q) = t^q`

`(2x^(-2)y^2)/(y^(-3))`

`color(white)("XXX")=(2y^2)/1 * (x^-2)/1 * 1/(y^(-3))`

`color(white)("XXX")=(2y^2)/1*1/x^2*y^3/1`

`color(white)("XXX")=(2y^5)/(x^2)`