How do you rewrite $((m^-3n^5)/(mn^-2))^2$ using a positive exponent?

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Answer 1 · 2015-10-19T19:28:32

$n^14/m^8$ is the simplified version of the expression with all positive exponents.

Begin by moving all of the exponents to the numerator.

$((m^-3n^5)/(mn^-2))^2$

the expression becomes,
$(m^-3m^-1n^5n^2)^2$
the exponents change sign when they are brought from the
denominator to the numerator

Combine the exponents for the similar variables
$(m^(-3-1)n^(5+2))^2$

$(m^-4n^7)^2$
Now distribute the exponent outside the parenthesis to the
exponents inside by multiplication.
$m^-8n^14$

Now move the variable with the negative exponent to the denominator to make the exponent positive.
$n^14/m^8$

How do you rewrite ((m^-3n^5)/(mn^-2))^2((m^-3n^5)/(mn^-2))^2 using a positive exponent?