How do you rewrite the equation 2x + 3y = 6 in slope-intercept form?

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Answer 1 · 2016-05-06T16:43:47

$y = -2/3x+2$

Isolate $y$ on the left hand side of the equation as follows:

Given:

$2x+3y=6$

Subtract $2x$ from both sides to get:

$3y = -2x+6$

Divide both sides by $3$ to get:

$y = -2/3x+2$

This is in slope intercept form:

$y = mx+c$

with slope $m=-2/3$ and ( $y$ ) intercept $c=2$ .