How do you simplify #1/2( 3 + 4^2) # using order of operations? Algebra Expressions, Equations, and Functions PEMDAS 1 Answer Özgür Özer Dec 3, 2015 #1/2(3+4^2)=19/2# Explanation: #1/2(3+4^2)=1/2(3+16)# #=1/2*19# #=19/2# Answer link Related questions What is PEMDAS? How do you use PEMDAS? How do you use order of operations to simplify #3(7-2)-8#? What are common mistakes students make with PEMDAS? How do you evaluate the expression #5[8+(3-1)]-2#? How do you simplify the expression #4(30-(3+1)^2)#? How do you evaluate the expression #x^4+x# if x=2? Is it okay to add first before subtracting in #4-6+3#? How do you simplify #(-3)^2+12*5#? How do you simplify #(4-2)^3-4*8+21div3#? See all questions in PEMDAS Impact of this question 1305 views around the world You can reuse this answer Creative Commons License