How do you simplify $\frac{1}{2} [6 - 4^{2}]$ $1/2[6-4^2]$ ?

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Answer 1 · 2016-07-03T17:22:44

$- 5$ $-5$

The first step is always to count the number of terms.
There must be a final answer for each term before they can be added or subtracted.

This is only one term, but there are 2 terms inside the parentheses.

$\frac{1}{2} [6 - 4^{2}] = \frac{1}{2} [6 - 16]$ $1/2[ 6 - color(red)(4^2)] = 1/2[6-color(red)16]$

= $\frac{1}{2} [- 10] = - 5$ $1/2[-10] = -5$

Or using the distributive law, we can get two terms at the beginning:

$\frac{1}{2} \times 6 - \frac{1}{2} \times 4^{2}$ $1/2xx6 - 1/2 xx 4^2$

$= 3 - \frac{1}{2} \times 16$ $= 3 - 1/2 xx 16$

$= 3 - 8 = - 5$ $=3 -8 = -5$

How do you simplify 12[6−42]1/2[6-4^2]?